Question Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input. class Solution: def merge(self, intervals: List[List[int]]) -> List[List[int]]: intervals.sort(key=lambda x: x[0]) merged = [] for interval in intervals: # if the list of merged intervals is empt..